ΠΟΥ ΧΑΘΗΚΑΤΕΕΕΕΕΕΕΕΕΕ????????????????????????????????????????
ΚΑΛΑ ΧΡΙΣΤΟΥΓΕΝΝΑ! ΧΡΟΝΙΑ ΠΟΛΛΑ ΣΕ ΟΛΟΥΣ ΤΟΥΣ ΜΕΛΟΝΤΙΚΟΥΣ ΣΥΝΑΔΕΛΦΟΥΣ ΚΑΙ ΣΤΟΝ ΜΕΓΑ INSTRACTORA ΜΑΣ( ΔΕΝ ΕΙΝΑΙ ΓΛΥΨΙΜΟ!!!!!!!!!!!)!!!ΟΤΙ ΕΠΙΘΥΜΕΙΤΕ ΜΕ ΠΑΝΩ ΑΠΟ ΟΛΑ ΥΓΕΙΑ ΜΕΤΑ ΕΥΤΥΧΙΑ ΚΑΙ ΕΠΙΤΥΧΙΑ ΠΡΟΣΩΠΙΚΗ ΚΑΙ ΦΥΣΙΚΑ ΕΠΑΓΓΕΛΜΑΤΙΚΗ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Thursday, December 25, 2008
Saturday, November 22, 2008
Subnetting Links
Στα παρακάτω link θα βρείτε ασκήσεις για vlsm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_1.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_2.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_2_ans.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_3.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_3_ans.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_4.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_4_ans.htm
Εξαιρετική πηγή ερωτήσεων για κάθε είδος subnetting. Σας δίνει άμεσα και την απάντηση.
http://www.subnettingquestions.com/
http://www1.fccj.cc.fl.us/cschmidt/vlsm_1.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_2.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_2_ans.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_3.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_3_ans.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_4.htm
http://www1.fccj.cc.fl.us/cschmidt/vlsm_4_ans.htm
Εξαιρετική πηγή ερωτήσεων για κάθε είδος subnetting. Σας δίνει άμεσα και την απάντηση.
http://www.subnettingquestions.com/
Subnetting #3
Find the Class each IP address belong to.
- 10.250.1.1
- 150.10.15.0
- 192.14.2.0
- 148.17.9.1
- 193.42.1.1
- 126.8.156.0
- 220.200.23.1
- 230.230.45.58
- 177.100.18.4
- 119.18.45.0
- 249.240.80.78
- 199.155.77.56
- 117.89.56.45
- 215.45.45.0
- 199.200.15.0
- 95.0.21.90
- 33.0.0.0
- 158.98.80.0
- 219.21.56.0
Network & Host Part Identification
Circle the network portion of these addresses:
177.100.18.4
119.18.45.0
209.240.80.78
199.155.77.56
117.89.56.45
215.45.45.0
192.200.15.0
95.0.21.90
33.0.0.0
158.98.80.0
217.21.56.0
10.250.1.1
150.10.15.0
192.14.2.0
148.17.9.1
193.42.1.1
126.8.156.0
220.200.23.1
10.15.123.50
171.2.199.31
198.125.87.177
223.250.200.222
17.45.222.45
126.201.54.231
191.41.35.112
155.25.169.227
192.15.155.2
123.102.45.254
148.17.9.155
100.25.1.1
195.0.21.98
25.250.135.46
171.102.77.77
55.250.5.5
218.155.230.14
10.250.1.1
Default Subnet Masks
Write the correct default subnet mask for each of the following addresses:
177.100.18.4 ____________________________
119.18.45.0 _____________________________
191.249.234.191 _________________________
223.23.223.109 _________________________
10.10.250.1 ____________________________
126.123.23.1 ___________________________
223.69.230.250 _________________________
192.12.35.105 __________________________
77.251.200.51 __________________________
189.210.50.1 __________________________
88.45.65.35 ___________________________
128.212.250.254 ________________________
193.100.77.83 __________________________
125.125.250.1 __________________________
1.1.10.50 _____________________________
220.90.130.45 _________________________
134.125.34.9 ___________________________
95.250.91.99 __________________________
Subnetting #2
Given an address and number of borrowed bits find the following information:
Address: 196.111.83.0
Number of Bits Borrowed: 5
Network Class__________________________
Number of Total Subnets _______________
Number of Total Hosts per subnet ________ Number of Usable Hosts_______
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Given an address and number of total subnets find the following information:
Address: 207.32.65.0
Number of Bits Borrowed: _________
Network Class_________
Number of Total Subnets: 8
Number of Total Hosts per subnet ________Number of Usable Hosts ________
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Given an address and number of total subnets find the following information:
Address: 183.41.0.0
Number of Bits Borrowed: _______
Network Class________
Number of Total Subnets: 254
Number of Total Hosts per subnet ________
Number of Usable Hosts ________
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Given an address and number of borrowed bits find the following information:
Address: 129.165.0.0
Number of Bits Borrowed: 4
Network Class__________________________
Number of Total Subnets _______________
Number of Total Hosts per subnet ________ Number of Usable Hosts ________
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Να βρείτε τα 3 ΤΕΛΕΥΤΑΙΑ subnets σε κάθε περίπτωση. (Network Address, Broadcast, 1st Host, Last Host)
Address: 196.111.83.0
Number of Bits Borrowed: 5
Network Class__________________________
Number of Total Subnets _______________
Number of Total Hosts per subnet ________ Number of Usable Hosts_______
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Given an address and number of total subnets find the following information:
Address: 207.32.65.0
Number of Bits Borrowed: _________
Network Class_________
Number of Total Subnets: 8
Number of Total Hosts per subnet ________Number of Usable Hosts ________
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Given an address and number of total subnets find the following information:
Address: 183.41.0.0
Number of Bits Borrowed: _______
Network Class________
Number of Total Subnets: 254
Number of Total Hosts per subnet ________
Number of Usable Hosts ________
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Given an address and number of borrowed bits find the following information:
Address: 129.165.0.0
Number of Bits Borrowed: 4
Network Class__________________________
Number of Total Subnets _______________
Number of Total Hosts per subnet ________ Number of Usable Hosts ________
Default subnet mask ____________________
Subnet mask (after subnetting) _______________________________
Να βρείτε τα 3 ΤΕΛΕΥΤΑΙΑ subnets σε κάθε περίπτωση. (Network Address, Broadcast, 1st Host, Last Host)
Subnetting #1
1.Which IP addresses are network addresses? (Choose two.)
A.64.104.3.7/28
B.192.168.12.64/26
C.192.135.12.191/26
D.198.18.12.16/28
E.209.165.200.254/27
F.220.12.12.33/27
2.A network administrator is building a network for a small business that has 22 hosts. The ISP has assigned only one Internet routable IP address. Which IP address block can the network administrator use to address the network?
A.10.11.12.16/28
B.172.31.255.128/27
C.192.168.1.0/28
D.209.165.202.128/27
3.What subnet mask would be used with the hosts in the 128.107.176.0 /22 network?
A.255.0.0.0
B.255.248.0.0
C.255.255.252.0
D.255.255.255.0
E.255.255.255.252
4.You have been assigned the address block 10.255.255.224 /28 to create the network addresses for point-to-point WAN links. How many of these WANs can you support with this address block?
A.1
B.4
C.7
D.14
5.A network administrator needs to create a new network that has 14 computers and two router interfaces. What subnet mask will provide the appropriate number of IPv4 addresses for this network with minimal wasted addresses?
A.255.255.255.128
B.255.255.255.192
C.255.255.255.224
D.255.255.255.240
E.255.255.255.248
F.255.255.255.252
6.List the ranges of IPv4 addresses for private use.
A.64.104.3.7/28
B.192.168.12.64/26
C.192.135.12.191/26
D.198.18.12.16/28
E.209.165.200.254/27
F.220.12.12.33/27
2.A network administrator is building a network for a small business that has 22 hosts. The ISP has assigned only one Internet routable IP address. Which IP address block can the network administrator use to address the network?
A.10.11.12.16/28
B.172.31.255.128/27
C.192.168.1.0/28
D.209.165.202.128/27
3.What subnet mask would be used with the hosts in the 128.107.176.0 /22 network?
A.255.0.0.0
B.255.248.0.0
C.255.255.252.0
D.255.255.255.0
E.255.255.255.252
4.You have been assigned the address block 10.255.255.224 /28 to create the network addresses for point-to-point WAN links. How many of these WANs can you support with this address block?
A.1
B.4
C.7
D.14
5.A network administrator needs to create a new network that has 14 computers and two router interfaces. What subnet mask will provide the appropriate number of IPv4 addresses for this network with minimal wasted addresses?
A.255.255.255.128
B.255.255.255.192
C.255.255.255.224
D.255.255.255.240
E.255.255.255.248
F.255.255.255.252
6.List the ranges of IPv4 addresses for private use.
Friday, November 21, 2008
Tuesday, November 18, 2008
Practice #3
| 238.13.15.174/19 167.147.106.75/11 243.118.243.61/20 74.141.41.46/27 177.161.55.167/18 220.126.161.117/21 90.67.197.253/22 132.254.210.179/27 58.76.96.68/9 32.2.52.148/20 114.163.100.60/8 9.149.116.155/16 191.230.131.28/30 204.153.57.225/28 | 52.46.136.83/12 242.137.228.219/30 251.200.23.72/18 184.56.75.20/29 23.253.106.26/9 214.146.124.237/26 36.202.21.96/12 59.90.128.100/20 20.167.194.232/10 206.233.20.201/17 242.67.244.122/18 46.244.112.137/9 162.69.199.150/15 113.70.3.230/29 |
Ισχύει και για τα προηγούμενα posts. Μπορείτε να μου στείλετε τις απαντήσεις σας στο mail μου για διόρθωση.
Practice #2
Επειδή είδα κατά την διάρκεια του μαθήματος μια μικρή δυστοκία στις μετατροπές από δεκαδικό ορίστε μερικοί αριθμοί για μετατροπή:
| 158 12 173 49 232 232 129 52 188 80 186 110 96 123 77 222 | 111 200 69 122 239 107 11 80 208 147 206 22 255 240 248 252 |
Practice #1
Αρχίζουμε λοιπόν την εξάσκηση:
Μετατροπή από δυαδικό σε δεκαδικό:
| 01011110 01010110 01001110 10001001 01101110 10001101 01100010 11011000 11000111 10100001 01111001 10011100 00100111 01001011 10111100 00011100 11101000 01001011 11000101 01001110 10110100 00011111 11000010 | 11000010 |
Thursday, October 30, 2008
Assessments
Όπως σας είπα και σήμερα στο μάθημα ενεργοποίησα τα assessments για τα κεφάλαια 2 και 3. Παρακαλώ μέχρι το επόμενο μάθημα να έχουν ολοκληρωθεί από όλους σας. Στην διάθεση σας για όποια απορία.
Sunday, October 26, 2008
Χρόνια πολλά
Καλημέρα παιδιά,
Χρόνια πολλά στους εορτάζοντες σήμερα (2 μέλη βλέπω, συγνώμη αν ξεχνάω κάποιον, αρχή είναι ακόμα), και καλά ... διαβάσματα (σε όλους μας)!!!
Τα λέμε την Πέμπτη.
Χρόνια πολλά στους εορτάζοντες σήμερα (2 μέλη βλέπω, συγνώμη αν ξεχνάω κάποιον, αρχή είναι ακόμα), και καλά ... διαβάσματα (σε όλους μας)!!!
Τα λέμε την Πέμπτη.
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